(x^4-81)/(x^3-4x^2-9x+36)

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Solution for (x^4-81)/(x^3-4x^2-9x+36) equation:


D( x )

x^3-(4*x^2)-(9*x)+36 = 0

x^3-(4*x^2)-(9*x)+36 = 0

x^3-(4*x^2)-(9*x)+36 = 0

x^3-4*x^2-9*x+36 = 0

x^3-4*x^2-9*x+36 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 9, -9, 12, -12, 18, -18, 36, -36 }

1

x = 1

x^3-4*x^2-9*x+36 = 24

1

-1

x = -1

x^3-4*x^2-9*x+36 = 40

-1

2

x = 2

x^3-4*x^2-9*x+36 = 10

2

-2

x = -2

x^3-4*x^2-9*x+36 = 30

-2

3

x = 3

x^3-4*x^2-9*x+36 = 0

3

x-3

x^2-x-12

x^3-4*x^2-9*x+36

x-3

3*x^2-x^3

36-x^2-9*x

x^2-3*x

36-12*x

12*x-36

0

x^2-x-12 = 0

DELTA = (-1)^2-(-12*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+1)/(1*2) or x = (1-49^(1/2))/(1*2)

x = 4 or x = -3

x in { -3, 4, 3}

x in (-oo:-3) U (-3:3) U (3:4) U (4:+oo)

(x^4-81)/(x^3-(4*x^2)-(9*x)+36) = 0

(x^4-81)/(x^3-4*x^2-9*x+36) = 0

x^3-4*x^2-9*x+36 = 0

x^3-4*x^2-9*x+36 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 9, -9, 12, -12, 18, -18, 36, -36 }

1

x = 1

x^3-4*x^2-9*x+36 = 24

1

-1

x = -1

x^3-4*x^2-9*x+36 = 40

-1

2

x = 2

x^3-4*x^2-9*x+36 = 10

2

-2

x = -2

x^3-4*x^2-9*x+36 = 30

-2

3

x = 3

x^3-4*x^2-9*x+36 = 0

3

x-3

x^2-x-12

x^3-4*x^2-9*x+36

x-3

3*x^2-x^3

36-x^2-9*x

x^2-3*x

36-12*x

12*x-36

0

x^2-x-12 = 0

DELTA = (-1)^2-(-12*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+1)/(1*2) or x = (1-49^(1/2))/(1*2)

x = 4 or x = -3

x in { -3, 4, 3}

(x+3)*(x-4)*(x-3) = 0

(x^4-81)/((x+3)*(x-4)*(x-3)) = 0

1*x^4 = 81 // : 1

x^4 = 81

x^4 = 81 // ^ 1/4

abs(x) = 3

x = 3 or x = -3

x in { 3}

x in { -3}

x belongs to the empty set

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